JEE Main 2020 Result: Scorecard, Cut Off and Merit List

Latest: NTA has released JEE Main 2020 Result for Paper 2 (B. Arch) and Paper 3 (B. Planning) on 23 January 2020. 2 candidates scored 100 NTA Score in B.Arch examination and 1 candidate scored 100 NTA Score in B. Planning.

Click here to check result

JEE Main 2020 Result has been announced in the form of percentile scores also called NTA score based on pre-defined normalization methodology. No cut off will be mentioned on the scorecard this year. The JEE Main 2020 Result can be downloaded from the official website using the JEE Main Application number and date of birth.

An important point to note here is that NTA released JEE Main 2020 Result for January session 15 days before the scheduled date. This result was supposed to be declared on 31 January, 2020.

JEE Main 2020 Result: Important Dates

The JEE Main 2020 Result for April session will be announced soon after the exam is successfully conducted. The JEE Main Exam has been delayed due to COVID-19 pandemic all over the country. Given below are the important dates with respect to JEE Main 2020 Result.

EVENTS	DATES
January Session
JEE Main Exam dates	6-9 January 2020
JEE Main Result (Paper 1 )	17 January 2020
JEE Main Result (Paper 2 & 3)	23 January 2020
April Session
JEE Main Exam dates	18-23 July, 2020
JEE Main Result	To be announced (Postponed)

Candidates can predict their rank using JEE Main Rank Predictor here

The final cutoff will be declared after compiling JEE Main 2020 Result scores of January and April session using the normalization process where scores are adjusted depending upon the difficulty level of each paper. 

JEE Main 2020 Result for April Session will be declared for Paper 1 (B.E/B.Tech), Paper 2 (B.Arch) and Paper 3 (B.Planning) separately. NTA will release final JEE Main Answer Keys for all the papers prior to the result declaration. Candidates not satisfied with the answer could send their representation against the answer key released before final answer keys.

How to Check JEE Main 2020 Result?

To check your JEE Main 2020 Result for January session, candidates have to visit the official site and login with their details.

Steps to check the JEE Main 2020 Result and downloading the scorecard are mentioned below:

• Go to the official site of JEE Main 2020 – jeemain.nic.in.

• Now click on the View Result/Scorecard button.
• Enter the required details such as Application Number, Date of Birth and Security Pin.

• Enter the security pin as given in the picture.
• Click on the ‘Submit’ button.
• Verify and Download JEE Main 2020 Result Scorecard.
• Save it as a PDF file or take a print out of JEE Main 2020 Scorecard for future use.

Applicants should ensure the details mentioned on JEE Main 2020 Scorecard are correct and match with their JEE Main Admit Card/Hall Ticket.

Details mentioned on JEE Main Scorecard

Following are the particulars display on the scorecard:

• Name of applicant
• Mother’s Name
• Father’s Name
• Nationality
• State Code of eligibility
• Gender
• Category
• Date of Birth of applicant
• Roll number of the applicant
• Applicant’s photograph
• Signature
• Subject wise NTA scores
• Total NTA Score

What does the JEE Main 2020 Result Scorecard look like?

Given below is an image of the JEE Main Scorecard. The format of scorecard changes from year to year. The image below is from the JEE Main 2020 Result for January 2020 session.

As visible above, scores of each examination is segregated in the JEE Main 2020 Result of JEE Main Scorecard. NTA has also provided the explanation over how the NTA Score of a candidate is calculated. As visible in the image above, these scores are normalized according to relative performance and difficulty levels of the JEE Main examination.

JEE Main 2020 Result: Toppers

Here is a list of all the toppers who have achieved a total NTA score 100 in JEE Main 2020 for January session. Toppers list published by NTA on 17th January 2020 for B.E/B.Tech is mentioned below:-

APPLICATION NUMBER	CANDIDATE’S NAME	STATE CODE OF ELIGIBILITY
200310065452	Landa Jitendra	ANDHRA PRADESH
200310404791	THADAVARTHI VISHNU SRI SAI SANKAR	ANDHRA PRADESH
200310120506	Nishant Agarwal	Delhi
200310012227	Nisarg Chadha	Gujrat
200310041891	DIVYANSHU AGARWAL	Haryana
200310436560	Akhil Jain	Rajasthan
200310166791	PARTH DWIVEDI	Rajasthan
200310594754	RONGALA ARUN SIDDARDHA	Telangana
200310386279	CHAGARI KOUSHAL KUMAR REDDY	Telangana

State-wise Toppers and their NTA Scores in B.E./B.Tech

State Code of Eligibility	Application No.	Candidates Name	NTA Score
Andaman and nicobar islands	200310373222	Akshat singh	97.3286395
Andhra pradesh	200310065452	Landa jitendra	100
Andhra pradesh	200310404791	Thadavarthi vishnu sri sai sankara	100
Arunachal pradesh	200310048155	Apurba nath	96.1831211
Assam	200310146902	Eeshaan dutta	99.9338277
Bihar	200310061027	Shubh kumar	99.9972380
Chandigarh	200310541037	Kanwarpreet singh	99.9972380
Chhattisgarh	200310180940	Shashwat chakraborty	99.9551322
Dadra and nagar haveli	200310380942	Sharad vishwakarma	99.2655484
Daman and diu	200310081203	Jain anmol rajesh kumar	98.6482824
Delhi(Nct)	200310120506	Nishant agarwal	100
Goa	200310128096	Siddhant govekar	99.9109245
Gujarat	200310012227	Nisarg chadha	100
Haryana	200310041891	Divyanshu agarwal	100
Himachal pradesh	200310018481	Sarthak diwan	99.9683001
Jammu and kashmir	200310448405	Aryan gupta	99.7338263
Jharkhand	200310154294	Dayal kumar	99.9909553
Karnataka	200310159880	Shubhankar	99.9965251
Kerala	200310049812	Advaid deepak	99.9737696
Ladakh	200310220758	Parveez mehdi	96.5201553
Lakshadweep	200310474502	Farzeenh	91.5220543
Madhya pradesh	200310023789	Akarsh jain	99.9959069
Maharashtra	200310175433	Vedang dhirendra asgaonkar	99.9972435
Manipur	200310295160	Chetan Raj kumari	97.3220500
Meghalaya	200310722265	Palais chakma	96.3974118
Mizoram	200310916691	Harshinis	91.1044385
Nagaland	200310044472	Alemmeren jamir	89.7388895
Odisha	200310104782	Sourabh soumya kanta das	99.9924070
Outside india	200310292707	Nilay mankala	99.5839421
Puducherry	200310135250	Harishr	99.9159086
Punjab	200310244253	Ujjwal mehta	99.9993109
Rajasthan	200310436560	Akhil Jain	100.0000000
Rajasthan	200310166791	Parth Dwivedi	100.0000000
Sikkim	200310149887	Arnav Vyas	98.0859130
Tamilnadu	200310237888	Gauravr kochar	99.9959069
Telangana	200310594754	Rongala arun siddardha	100.0000000
Telangana	200310386279	Chagari koushal kumar reddy	100.0000000
Tripura	200310663342	Gaurav malakar	99.9095741
Uttarpradesh	200310041750	Gokulnath	99.9993050
Uttarakhand	200310174584	Bashar ahmed	99.9930425
Westbengal	200310113393	Sreemanti dey	99.9923468

JEE Main 2020 Result Toppers – B.Arch and B. Planning

NTA has released JEE Main 2020 toppers list for B.Arch and B. Planning on its official website. Candidates can check the table mentioned below:-

APPLICATION NO.	CANDIDATE’ NAME	STATE CODE OF ELIGIBILITY
B. Arch
200310344799	AARZOO	Haryana
200310587193	HARDIK RAJPAL	Telangana
B. Planning
200310486570	KANUMURI BHEEMESWARA VIJAY VARMA	ANDHRA PRADESH

JEE Main 2019 Toppers – April Session

NTA will release the Topper list of JEE Main April session after the JEE Main 2020 Result declaration. Meanwhile, candidates can check below the list of top percentile scorers of JEE Main 2019 April Session Toppers list published by NTA.

JEE Main Top Percentile Scorers (NTA Score)

Sr.No	Application Number	Name of the Candidate	State Name
1	190310042962	Shubham Srivastava	Delhi
2	190310208678	Kevin Martin	Karnataka
3	190310086378	Dhruv Arora	Madhya Pradesh
4	190310378068	Jayesh Singla	Punjab
5	190310244684	Battepati Karthikeya	Telangana
6	190310263619	Nishant Abhangi	Rajasthan
7	190310126508	Adelly Sai Kiran	Telangana
8	190310167837	Viswanath K	Telangana
9	190310167372	Konda Renu	Andhra Pradesh
10	190310274885	Abhay Pratap Singh Rathore	Madhya Pradesh
11	190310139257	Sambit Behera	Rajasthan
12	190310240908	Shubhankar Gambhir	Rajasthan
13	190310324762	Ankit Kumar Misra	Maharashtra
14	190310204122	Himanshu Gaurav Singh	Uttar Pradesh
15	190310059556	Prakhar Jagwani	Madhya Pradesh
16	190310036034	Dravya Marwaha	Haryana
17	190310150035	Naman Gupta	Uttar Pradesh
18	190310597090	Gupta Kartikey Chandresh	Maharashtra
19	190310166518	Yindukuri Jayanth Phani Sai	Telangana
20	190310238084	Samiksha Das	Rajasthan
21	190310131614	Bojja Chetan Reddy	Andhra Pradesh
22	190310122769	Gudipaty Aniket	Jharkhand
23	190310357149	Jitender Kumar Yadav	Haryana
24	190310096437	Raj Aryan Agrawal	Maharashtra

JEE Main 2020 Seat Matrix

JEE Main 2020 Seat Matrix shows the number of seats available from JEE Main towards NITs, IIITs and GFTIs. Other than this, seats are available in other private colleges as well. The Seat Matrix includes seats for all the institutions taking part in the Counselling Process of JEE Main 2020. Given below is an estimated data of JEE Main 2020 Seat Matrix based on the data of previous years.

Category	Total Seats	GFTIs	IIITs	NITs	IITs
Open	19713	2898	1991	8897	5927
Open-PWD	962	146	91	442	283
SC	6391	796	663	2993	1939
SC-PWD	343	43	43	160	97
ST	395	459	340	1827	969
ST-PWD	197	21	14	108	54
OBC	10972	1061	1200	5212	3499
OBC – PWD	566	59	66	272	169
Total Seats	38704	5635	4449	17452	11168

How to calculate JEE Main 2020 Result?

The JEE Main 2020 Result is calculated in the form of a percentile NTA score for Physics, Chemistry, and Mathematics and a combined score. The NTA scores are obtained by normalization using the raw score gained by the candidates. The following formula is used to obtain the NTA score-

The NTA scores of candidates in JEE Main exam will be used to compute the ranks. The AIR is affected directly by the scores obtained in Joint Entrance Exam i.e. higher the scores, better the rank in JEE Main. In case, two or more candidates score equal marks, then the tie-breaking rule or inter-se-merit will be applicable.

Is the Percentile Score and NTA Score the same?

Yes, Percentile score and NTA score of JEE Main 2020 Result are the same thing. Although, there is a slight difference in the calculation which gives the chance of scoring a full 100 NTA score to candidates. The percentile score is basically an easier form of representing the rank of a candidate appearing for the examination. The Normalized NTA score is usually calculated after representing the scores on a scale ranging from 100 to 0 for each session. JEE Main 2020 Result has-

1. NTA Score for Subject 1
2. NTA Score for Subject 2
3. NTA Score for Subject 3
4. Total NTA Score

According to the official website of NTA or Information Bulletin published by NTA, “The Percentile Score indicates the percentage of candidates that have scored EQUAL TO OR BELOW (same or lower raw scores) that particular Percentile in that examination. Therefore, the topper (highest score) of each session gets the same Percentile of 100 which is desirable. The marks obtained in between the highest and lowest scores are also converted to appropriate Percentiles.”

How is the JEE Main 2020 Result compiled from two sessions?

As given above, NTA scores of all 3 subjects and the total NTA Score are given in the JEE Main 2020 Result Scorecard. For candidates attempting both, January and April session of JEE Main 2020, scores will be merged. This does not mean that the score will be added altogether.

• Comparison will be made in NTA scores of each subject.
• The final NTA score will be considered from the attempt with two or more greater NTA scores compared to the other attempt (best of two).
• Final NTA Score will be based on the attempt considered as above.
• This NTA score will also be used for Merit Lists/Rankings.

Normalization Procedure for JEE Main 2020 Result

National Testing Agency will conduct JEE Main 2020 in two shifts over a span of 3 to 5 days i.e. from 18th to 23rd July 2020 (postponed due to COVID-19). Various sets of papers are designed for each shift and to maintain equivalence of scores, no two shifts have the same question repeating even from a set of a previously held JEE Main paper. However, the difficulty level of these papers from various sessions might not remain the same. Thus it is possible that a few candidates may ultimately attempt a relatively tougher set of questions when compared to other sets. The candidates who attempt the comparatively difficult examination are likely to get lower marks as compared to those who attempt the easier one. In order to overcome such a situation,“Normalization procedure based on Percentile Score” will be used to ensure that candidates are neither at a benefit or at a disadvantage because of the various difficulty levels of the examination. Thus, in order to bring a symmetry over the difficulty scale with context to the issues mentioned above, the Normalization Procedure will be used for JEE Main 2020.

How do top scorers benefit from Normalization Procedure?

As mentioned before, the Percentile Score and NTA Score of a candidate is the same. But it might still be unclear how two candidates – one scoring 332 marks in a particular shift, while other scoring 346 marks in another shift – would have a full 100 NTA Score. Given below is an example of the same-

Suppose the examination was held on two days in two shifts. This will be calculated as 4 sessions.

Now, in all these sessions, the highest raw scorer will always have the highest NTA Score i.e. 100. This means that 100% of candidates in that particular session have a score equal to or less than the highest scorer/topper for the particular session. Given below is a table for calculation of NTA scores (percentile) of toppers.

This shows that all the highest raw scores would be normalized to 100 Percentile Score for their respective session in JEE Main 2020 using the Normalization Procedure.

Tie-Breaking Rule for JEE Main 2020 Result

Tie-breaker rule is nothing but the criteria on which the candidate for higher rank will be selected if there is a tie or equivalence between marks of two candidates. Usually, this does not affect the rank or percentile of a candidate by huge degree. Given below are the rules for various Papers of JEE Main 2020.

JEE Main Paper 1 (B.Tech/B.E)

• NTA Score in Mathematics: Candidate who gets more percentile score in Mathematics will be ranked higher
• NTA Score in Physics: Candidate who gets more percentile score in Physics will be ranked higher
• NTA Score in Chemistry: Candidate who gets more percentile score in Chemistry will be ranked higher
• Date of Birth: The older candidate between the two will be ranked higher 

Note: In case the tie still remains undetermined, the same rank is given to both the candidates.

JEE Main 2020 Paper 2 (B.Arch)

• NTA Score in Mathematics: Candidate who scores higher marks in maths section will be given a higher rank
• NTA Score in Aptitude Test: Candidate with a higher score in the aptitude test will be allotted a higher rank
• NTA Score in Drawing Test: Candidate with higher scores in the drawing test will be allotted a higher rank
• Less negative response: Candidates having lesser number of negative responses in the paper will be given higher rank
• Date of Birth: The older candidate will be ranked higher between the two

JEE Main 2020 Paper 3 (B.Planning)

• NTA Score in Mathematics: Candidate who obtain higher marks in Mathematics section will be given a higher rank
• NTA Score in Aptitude Test: If the tie remains, candidate with higher score in aptitude section will be given a higher rank
• NTA Score in Planning Based Questions: If all rules above do not break the tie, then the candidate with higher marks in planning based questions will be given the higher rank
• Less negative response: Candidate having less number of negative responses in the paper will be ranked higher
• Date of Birth: The older candidate will be ranked higher between the two

JEE Main 2020 Marks Vs Rank

The following table depicts the approximate marks range for calculating the probable rank in JEE Main. The data given below is based on the old JEE Main Exam Pattern. For an analysis of this data, it is imperative to understand that the top 10 to 20 rankers of JEE Main usually score 40 to 50 marks below the maximum marks of the examination. It is also important to note that a rank of around 15,000 is considered good and will get you a percentile score of around 90 to 95%ile. Do remember that there are more than 11,00,000 applicants who appear for the JEE Main Examination.

Marks	Rank Range
301 to 360	1 – 9
281 to 300	10 – 83
261 to 280	84 – 244
241 to 260	245 – 706
221 to 240	707 – 1755
201 to 220	1756 – 4163
181 to 200	4164 – 8997
161 to 180	8998 – 18371
141 to 160	18372 – 35928
121 to 140	35929 – 67649
101 to 120	67651 – 125722
81 to 100	125723 – 237034
61 to 80	237035 – 463443
41 to 60	463444 – 844544
21 to 40	844546 – 1093113
1 to 20	1093115 – 1121966

JEE Main 2020 Answer Key

JEE Main 2020 Answer Keys will be released after the Computer-based exam is successfully conducted. Answer Keys are different for different sets of papers as the questions in various sets are jumbled up. Although the questions of all the sets in a particular shift might be indifferent. The JEE Main Answer Keys will be released at www.jeemain.nic.in.

• The answer keys will be available online until the result is announced.
• Those who are not satisfied with the captured response can challenge the JEE Main official answer keys along with the proof.
• A fee of INR 1000 per question will be charged for challenging the answer keys where the JAB’s/CBSE’s decision on the challenges will be final.

Downloading JEE Main 2020 Answer Keys

For downloading the JEE Main 2020 Answer Key, students need to follow the steps given below-

• Open the official website of JEE Main
• Click on the “View Answer Key and Question Paper” link.
• Students will be redirected to Login page
• Enter application number, password or date of birth, and then click on the Sign-in button
• The response key and answer key will appear on the screen
• After that students can cross-check the answer with correct option ID

Students are advised to download and take the printout of the JEE Main answer key for future reference. Given below are answer keys for JEE Main 2020 January Session.

JEE Main 2020 Answer Keys – January 7

The official JEE Main answer keys have been released by NTA for both Paper 1, Paper 2 and 3. Candidates can download the keys and question papers by Resonance Coaching Institute from below links:

Subject	Morning Shift	Evening Shift
Physics	Download	Download
Chemistry	Download	Download
Mathematics	Download	Download
Overall Analysis	Download	Download

JEE Main 2020 Answer Keys – January 8

Experts say that there will be an increment in this year’s cut off as the number of registered candidates and appearing candidates have increased and moderate to easy question papers have been set.

Subject	Morning Shift	Evening Shift
Physics	Download	Download
Chemistry	Download	Download
Mathematics	Download	Download
Overall Analysis	Download	Download

JEE Main Answer Key plays a crucial role as most candidates can plan their next move i.e., registering for counselling and seat allotment process based on their tentative scores.

JEE Main 2020 Answer Keys – January 9

Subject	Morning Shift	Evening Shift
Physics	Download	Download
Chemistry	Download	Download
Mathematics	Download	Download
Overall Analysis	Download	Download

JEE Main 2020 Result: Rank Lists

• A rank list will be set up according to the marks obtained by the candidate in the JEE Main examination.
• It will be released independently for paper 1 as well as paper 2. Check JEE Main Exam Pattern
• Admissions will be provided according to the rank achieved in the entrance test.
• The tie-breaking rule will be applied in case two or more applicants get equal marks.

JEE Main 2020 Result: Qualifying Cutoff

JEE Main 2020 Cutoff will be based on the overall data finally released by the Counselling Authority for JEE Main 2020. Meanwhile, candidates can check the JEE Main Cutoff for previous years to understand the trend seat allotment at highest and lowest ranks under various JEE Main Rank Lists.

JEE Main 2020 Expected Cutoff

Category	Cutoff for Paper 1
Common Rank List	89
General-EWS	78
Other Backward Classes (OBC-NCL)	74
Scheduled Caste (SC)	54
Scheduled Tribe (ST)	44
PwD	0

JEE Main Cutoff 2019

Reservation Category	JEE Main Cutoff for Paper 1
Common Rank List	89.7548849
General – EWS	78.2174869
Other Backward Classes (OBC-NCL)	74.3166557
Scheduled Caste (SC)	54.0128155
Scheduled Tribe (ST)	44.3345172
PwD	0.1137173

JEE Main Cutoff 2018

Category	Qualified	Maximum Marks	Minimum Marks
Common Rank List	111275	350	74
OBC-NCL	65313	73	45
SC	34425	73	29
ST	17256	73	24
PWD	2755	73	-35

What factors change the JEE Main Cutoff?

A large number of factors might be responsible for a change in JEE Main Cutoff for Counselling Rounds as well as admissions to various participating colleges. Joint Seat Allocation Board has announced that class 12th marks will not be given weightage for calculating AIRs in JEE Main 2020 Exam. Although colleges might weigh the same under their admission criteria. This might benefit students who do not have a great answer writing skills but have a good conceptual knowledge to find the right answers. On the other hand, major IITs do not take candidates below the minimum aggregate of around 90% in 12th boards due to high competition for seats in top courses of top IITs. But behind all this, the first step for every aspirant is to score the minimum cutoff of JEE Main to be qualified for JEE Advanced 2020. The following factors play a vital role in determining the JEE Main Cutoff every year-

• Total number of candidates appeared for the exam – Depending on the number of candidates, cutoff might increase or decrease. Usually the cutoff has remained between 110 to 80 for the past few years. The recent decrease in JEE Main Cutoff is not due to this factor but due to change in total marks of the JEE Main examination.
• Level of difficulty of exam – Various shifts of exams might have various difficulty levels. It is possible that a shift might have moderate to easy questions while another might have very difficult questions. Although this is usually normalized using the normalization process, the cutoff will be set in such a way that it benefits everyone equally.
• Number of available seats – Seat Matrix for JEE Main and JEE Advanced shows the low number of seats available under various counselling processes. Out of the 11 lakh applicants, probably 2 to 2.5 lakh are actually allotted seats. While the remaining candidates do get admission to a suitable college, it might not be at par with the top tier colleges of the country.
• Overall performance of the candidate – Cutoff is highly dependent on the quality of the batch. Recently, with improving educational techniques and highly skilled students, there has been a gradual rise in top performers. Competition is rising sharply and soon enough, cutoff might rise as well.

JEE Main 2020 Counselling Process

Under the complete JEE Main Counselling process, there are 3 main counselling processes, namely – JoSAA, CSAB SFTI and CSAB NEUT – conducting in the same sequence as stated before. More than 100 institutes and universities participate in the JEE Main Counselling and the JEE Main Admissions Process. Given below is a brief detail about various counselling processes-

• JoSAA Counselling is conducted for the qualified candidates of JEE Main and JEE Advanced. Only IITs conduct counselling from JEE Advanced scores.
• CSAB SFTI is the separate counselling procedure held by Central Seat Allocation Board or CSAB for 17 Self-Financed Technical Institutions (shortened to SFTI).
• CSAB NEUT is conducted for supernumerary seats in the North East and Union Territories (shortened to NEUT).

JoSAA Counselling after JEE Main 2020 Result

JoSAA will hold JEE Main Counselling and Seat Allotment for JEE Main and JEE Advanced candidates after the declaration of JEE Main 2020 Result.

• A total of 6 rounds will be conducted for admission.
• Based on marks scored in JEE Main, candidates will be called for JEE Main Counselling.
• 23 IITs, 31 NITs, 23 IIITs and 23 Other-Government Funded Technical Institutes (Other-GFTIs) will be participating in JEE Main Counselling.
• Counselling for IITs is based on the JEE Advance 2020 Results.
• The entire seat allocation and admission process would be managed through centralized JEE Main Counselling.

Eligibility for Joint Seat Allocation under JEE Main Counselling

There are a number of criteria introduced by the authorities and the candidates who satisfy one or more criteria become eligible for participation in Joint Seat Allocation.

CRITERIA 1	Qualified in JEE (Advanced) 2020 for academic programs [excluding the preparatory courses] at IITs.
	Performance in Class XII Examinations or any equivalent
CRITERIA 2	Qualified in JEE (Advanced) 2020 for preparatory courses at IITs
	Performance in Class XII Examinations or any equivalent
CRITERIA 3	Secured a rank in JEE (Main) 2020 Paper-1 for B.E./B.Tech. programs at NITs, IIEST, IIITs and Other-GFTIs
	Must have passed Class XII (or equivalent) examination* with Physics and Mathematics as compulsory subjects along with one of the Chemistry/Biotechnology/Biology/Technical Vocational subjects. Further, the candidate should have passed each subject individually as well
	Performance in Class XII Examinations or any equivalent
CRITERIA 4	Secured a rank in JEE (Main) 2020 Paper-2 for B.Arch./ B. Planning programs at NITs, IIEST, IIITs and Other-GFTIs
	must have passed Class XII (or equivalent) examination* with Mathematics as one of the subjects. Further, the candidate should have passed each subject individually as well
	Performance in Class XII Examinations or any equivalent

CSAB NEUT Counselling after JoSAA Counselling

The CSAB NEUT Counselling or Central Seat Allocation Board for North Eastern States and Union Territories is a counselling process to promote education in remote areas of the country. Given below are some details-

• According to the reservation laws of Government of India, candidates can apply for Technology/Engineering/Pharmacy/Architecture programs from AICTE approved institutes all over the country.
• The seats are usually reserved for engineering/polytechnic courses in the institutions based in these areas. This is due to lack of certain educational facilities in the said NEUT.
• List of states and UTs under CSAB NEUT are – Arunachal Pradesh, Sikkim, Tripura, Assam, Dadra and Nagar Haveli, Daman and Diu, Meghalaya, Mizoram, Andaman and Nicobar Islands, Manipur, Lakshadweep and Nagaland.

Eligibility for CSAB NEUT 2020 Counselling

To be eligible for CSAB NEUT Counselling, a candidate must have a valid JEE Main Result/Score. Besides this, an applicant who has not taken part in JoSAA Counselling, will be eligible for a special round of CSAB Counselling process for NITs, IIITs and GFTIs.

• For B.Tech or B.E Courses – Aspirants should pass 12th class with Mathematics and Physics. The candidates should have one of the following subjects – Biotechnology/Biology/Chemistry.
• 75% aggregate marks is mandatory for 12th for General and OBC-NCL. 65% limit is set for SC/SC/PwD.
• For B.Arch course – Should have in depth knowledge in Physics, Chemistry and Mathematics of Class 12. Mandatory subject is only Mathematics. Candidates must score at least 75% marks in aggregate to be eligible.
• Candidates applying for B.Arch courses, may also apply using NATA score. Many colleges prefer NATA scores than JEE Main scores.
• 75% marks in aggregate in class 12th is mandatory for a candidate who has planned to enrol for a B.Planning course in any college.

CSAB SFTI Counselling after JoSAA Counselling

The CSAB SFTI Counselling or Central Seat Allocation Board for Self-Funded Technical Institutes is the counselling process for 34 private universities/colleges which take part in the JEE Main Counselling process. Some of the famous participating colleges are Amity University Noida, Amity University Mumbai, Galgotias University Greater Noida. The registrations for CSAB SFTI counselling also begins after JoSAA counselling. Few details about CSAB SFTI Counselling are given below-

• Fee for registration of CSAB SFTI Counselling is INR 21,000. Payment must be made using SBI e-challan.
• Colleges have their own JEE Main Cutoffs for seats under various courses. Allotment of seats is done on a similar basis.
• Download the ‘Provisional Seat Allotment Letter’ from the official website of CSAB before taking part in the counselling process.
• All mandatory documents will be required at the time of final reporting to colleges to ensure eligibility of the candidates.

Eligibility for CSAB SFTI 2020 Counselling

Eligibility Rules for CSAB SFTI are similar to CSAB NEUT counselling. JEE Main 2020 Result/Score must be valid. Candidates must have not taken any seat under JoSAA Counselling. Other qualifications required for CSAB SFTI Counselling are given below-

• For B.E/B.Tech courses – 45% aggregate marks in 12th for General Category candidates. While 40% required for SC/ST/OBC-NCL/PwD.
• Maths and Physics is mandatory for this course. Passing marks should be achieved in all the 5 subjects of the qualifying examination.
• For B.Arch/B.Planning Courses – 50% aggregate marks is mandatory in 12th Board exams for all candidates.
• Mathematics is the only mandatory subject for B.Arch and B.Planning courses. Passing marks should be secured in all subjects.

JEE Main 2020 Result: Participating Colleges

There are many government funded colleges that offer admission based on the JEE Mains Scores. Various institutes like NITs, IITs, IIITs, GFTIs, some state colleges fill their seats on the basis of JEE Mains scores. Seats in private colleges are also filled using the scores of JEE Mains. Candidates are advised to check how JoSAA works to avoid mistakes in the counselling process.

National Institute Of Technology (NITs)

The admission in the National Institute of Technology (NITs) are based on JEE Mains scores. JoSAA conducts the counselling for filling the seats at various NITs across the country. There are a total of 31 NITs in the country which are categorised under autonomous public institutes. Out of the 31 NITs, 11 are relatively newly established while the remaining 20 are old engineering institutes

1. National Institute of Technology, Kurukshetra (Haryana)
2. National Institute of Technology, Nagpur (Maharashtra)
3. National Institute of Technology, Puducherry
4. National Institute of Technology, Goa
5. National Institute of Technology, Agartala
6. National Institute of Technology, Delhi
7. National Institute of Technology, Manipur (Imphal)
8. Malviya National Institute of Technology, Jaipur (Rajasthan)
9. National Institute of Technology, Silchar (Assam)
10. National Institute of Technology, Jamshedpur (Jharkhand)
11. National Institute of Technology, Nagaland
12. Motilal Nehru Institute of Technology, Allahabad (Uttar Pradesh)
13. National Institute of Technology, Tiruchirapalli
14. National Institute of Technology, Meghalaya
15. National Institute of Technology, Warangal (Tamil Nadu)

Indian Institute Of Information Technology (IIITs)

The Indian Institutes of Information Technology (IIITs) are autonomous institutions offering technical education focused on Information Technology and Communication Studies. IIITs are popular among the students after IITs and NITs.

The total number of IIITs in India are 25, five of which are listed as the Institutes of National Importance.

1. Indian Institute of Information Technology, Allahabad (Uttar Pradesh)
2. Indian Institute of Information Technology, Pune
3. Indian Institute of Information Technology, Guwahati
4. Atal Bihari Vajpayee Indian Institute of Information Technology and Management, Gwalior (Madhya Pradesh)
5. Indian Institute of Information Technology, Goa
6. Indian Institute of Information Technology, Lucknow (Uttar Pradesh)
7. Indian Institute of Information Technology, Nagpur (Maharashtra)
8. Indian Institute of Information Technology, Vadodara (Gujarat)
9. Indian Institute of Information Technology, Kota (Rajasthan)
10. Indian Institute of Information Technology, Jhalwa, Allahabad (Uttar Pradesh)
11. Indian Institute of Information Technology and Design and Manufacturing, Kanchipuram, Chennai (Tamil Nadu)
12. Indian Institute of Information Technology, Sri City, Chittaur (Andhra Pradesh)
13. Indian Institute of Information Technology, Manipur (Imphal)
14. Indian Institute of Information Technology, Sonepat (Haryana)
15. Indian Institute of Information Technology, Bhopal (Madhya Pradesh)

Government Funded Technical Institutes (GFTIs)

Government Funded technical Institutes (GFITs) accepts the score of JEE Mains for the admission in B.Tech/ B.E. curses. The allotment of B.Tech seats in GFTIs is based on the cut-off score of JEE Main. JoSAA conducts JEE Main counselling and seat allotment process for admission in IITs, NITs, IIITs and other GFTIs. Below are given some of the popular GFITs that offer admissions on the basis of scores obtained in JEE Mains.

1. Institute of Technology, Guru Ghasidas Vishwavidyalaya, Bilaspur, Chhattisgarh
2. National Institute of Electronics and Information Technology (NIELIT), Aurangabad, Maharashtra
3. Assam University, Silchar, Assam
4. Sant Longowal Institute of Engineering and Technology
5. Mizoram University, Aizawl
6. School of Planning and Architecture, Bhopal, Madhya Pradesh
7. Institute of Infrastructure, Technology, Research and Management (IITRAM), Ahmedabad, Gujarat
8. J.K. Institute of Applied Physics and Technology, University of Allahabad, Allahabad, Uttar Pradesh
9. Birla Institute of Technology, Mesra, Ranchi, Jharkhand
10. Institute of Carpet Technology, Bhadohi, Uttar Pradesh
11. School of Planning and Architecture, New Delhi
12. School of Planning and Architecture, Vijayawada
13. Gurukula Kangri Vishwavidyalaya, Haridwar
14. National Institute of Foundry and Forge Technology, Ranchi, Jharkhand
15. School of Engineering and Technology, Mizoram

States which accept JEE Main 2020 Result

Some states do accept the scores of JEE Mains. The seats in all the engineering colleges of the states are filled by the counselling which is done on the basis of the scores obtained in JEE mains examination. However, Some states have their own engineering entrance exams that are applicable on the engineering colleges of that particular state. The states that accept the score of JEE Mains are listed below:

1. Nagaland
2. Madhya Pradesh
3. Punjab
4. Rajasthan
5. Uttarakhand
6. New Delhi
7. Haryana
8. Odisha

Delhi Colleges accepting JEE Main 2020 Result

There are many engineering institutes in New Delhi that accept the scores of JEE Mains for filling up their seats. These colleges are known for their highly qualified and well-experienced faculty and have good placement records. They release their own cut off after the release of the JEE Mains cut off. Admissions are done on the basis of the cut off announced by them.

1. Delhi Technical University (DTU), New Delhi
2. Netaji Subhas Institute of Technology (NSIT), New Delhi
3. Jamia Millia Islamia, New Delhi
4. Jawaharlal Nehru University, New Delhi
5. School of Planning and Architecture, New Delhi
6. Indraprastha Institute of Information Technology, New Delhi
7. Jamia Hamdard, New Delhi
8. Apeejay Satya University, New Delhi
9. Indira Gandhi Delhi Technical University for Women (IGDTUw), New Delhi
10. National Institute of Technology, New Delhi

Private Colleges accepting JEE Main 2020 Result

There are many private institutes that also accept the score of JEE Mains to offer admission in the B.Tech/B.E Courses to the engineering aspirants. The list of some of the famous private engineering colleges is given below:

1. Birla Institute of Technology, Jaipur, Rajasthan
2. IISC Indian Institute of Science, Bangalore
3. Thapar Institute of Engineering and Technology, Punjab
4. Jamia Millia Islamia, New Delhi
5. PEC Punjab University of Technology, Chandigarh
6. Jaypee Institute of Technology, Noida, Uttar Pradesh
7. Amity Institute of Technology, Noida, Uttar Pradesh
8. AISECT University, Bhopal, Madhya Pradesh
9. Galgotias University, Greater Noida, Uttar Pradesh
10. Techno India University, Kolkata, West Bengal
11. ITM University, Gwalior, Madhya Pradesh
12. Dr KN Modi University, Tonk, Rajasthan
13. Bhagwant University, Amer, Rajasthan
14. Amity School of Engineering, Raipur, Chhattisgarh
15. Amity University, Gurgaon, Haryana