IIT Roorkee Cut Off 2020 will be announced by JoSAA (Joint Seat Allocation Authority) post the JEE Advanced 2020 exam. It defines the minimum rank or marks required by a candidate to get a seat at B.Tech admission offered at the Indian Institute of Technology (IIT), Roorkee.

Indian Institute of Technology Roorkee was inaugurated in 1847. It is the seventh IIT institution that was established among the IIT group of institutions. 75 courses across 5 streams are offered here. IIT Roorkee is spread over an area of 25 acres, some of the popular courses offered here include MSc, B.Tech and M.Tech Course. The JEE Advanced cut off ranks for any IIT including IIT Roorkee Cut Off means the closing ranks for each branch of the IIT.

• The admission cycle for B.Tech courses starts from December with JEE Main registrations.
• To get eligible for admissions at IIT Roorkee’s B.Tech course, candidates must comply with the eligibility criteria for JEE Main and JEE Advanced.
• JoSAA gives admissions to 107 institutes including 23 IITs, 31 NITs, 25 IIITs and 28 GFTIs.
• IIT Roorkee accepts admissions based on the JEE Advanced cut off list.
• The IIT Roorkee cut off list for the Civil Engineering (4 Years, Bachelor of Technology) stream was 5261 in 2019 as compared to 4756 in 2018.
• The IIT Roorkee cut off list for Applied Mathematics (5 Years, Integrated Master of Science) in 2019 was 2298, while it was 2470 in 2018.

Also Check | JEE Advanced Cut Off

IIT Roorkee 2019 Cut Off

The candidates with a minimum of 75% aggregate (SC/ST candidates get 10% relaxation) in Class 12 from a recognized board of education are eligible to fill the form. Candidates whose names are in the top 20 percentile in Class 12 are qualified to appear for the test. Candidates must have qualified JEE Main, with the all India rank of 2,25,000 as well as JEE Advanced.

IIT Roorkee 2019 cut off for B.Tech courses and B.Arch is mentioned below

Read More | JEE Advanced Reservation Criteria

IIT Roorkee Cut Off Comparison of Previous Years – 2018 and 2017

IIT Roorkee admission is getting more and more competitive each year, and the cut offs for each specialisation is getting higher.

Here is a comparison of IIT Roorkee previous year cut offs;

The IIT Roorkee Cut Off will be announced after taking the exams, the cut off list will be announced almost 30 days after the exam. For the meanwhile, the candidates can refer to the JEE Advanced cut off for 2019 to get a broader understanding.

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IIT Roorkee Cut Off Round 1

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IIT Roorkee Cut Off Round 2

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IIT Roorkee Cut Off Round 3

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IIT Roorkee Cut Off Round 4

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IIT Roorkee Cut Off Round 5

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IIT Roorkee Cut Off Round 6

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IIT Roorkee Cut Off Round 7

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The Indian Institute of Technology (IIT) Roorkee is one of the oldest IITs in India established in 1847. The Institute offers different undergraduate courses including B.Tech, integrated M.Sc, Integrated M.Tech, and B.Arch. Admission to UG programs in all IITs is granted based on the JEE (Advanced), the final merit list cut off list is prepared based on the candidate’s score. Candidates need to get qualified in JEE Advanced while GATE Cut off is needed to get admission for M.Tech and M.Arch.

IIT Roorkee offers Bachelors in 10 disciplines of Engineering and Architecture and Masters in 55 disciplines like Engineering, Science, Architecture and planning. The institute also has the facility for doctoral work in all Departments and Research Centers.

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IIT Roorkee Cut Off FAQs