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9.65 Lakh Candidates Applied for the JEE Main 2019 January Exam

JEE Main 2019 Registration for January session closed on Sep 30, 2018. The online CBT (Computer Based Test) exam for JEE Main 2019 Jan session would be held in between of Jan 6, 2018 and Jan 20, 2018. Over 9.65 lakhs aspirants have registered for JEE Main 2019 January exam.

In case, any candidate has made any errors in his/her application form, JEE Main Correction Window would get active from Oct 8, 2018 to Oct 14, 2018. Candidates may avail this one-time facility and edit the details correctly at nta.ac.in or jeemain.nic.in.

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Although the dates of JEE Main 2019 January session are coinciding with the XII class students’ practical board exam, it did not reflect much in the number of applications received from students by NTA.

NTA Positive About New JEE Main System

As NTA is conducting JEE Main for the first time, in two slots: January and April, the organization was expecting somewhere around 6 lakh registrations for January session. But to their surprise, the number of applicants turned out to be unexpectedly 9.65 Lakhs. Well, the new conducting authority is looking at it as a good sign as according to them, students have welcomed the decision of conducting the exam twice a year completely in online mode for the first time since its inception.

Other than this, NTA has set up more than 3400 test practice centers across the country to assist students in preparation of JEE Main 2019 which has also been appreciated very much by students.

As per the report, female applicants are just 2.8 lakhs (approx 29%) while applications from male candidates are 6.85 lakhs. Moreover, 38 transgenders have also applied for JEE Main 2019 January session.

The category wise list of applications is indicated below for JEE Main 2019:

Category Number of Applications
General Category 4.72 Lakhs
OBC 3.67 Lakhs
SC 0.89 Lakh
ST 0.36 Lakh

However, when compared to the registrations of the previous year, which were around 12 Lakhs, this year, the number of applicants has decreased by almost 2.5 lakhs.  The decreased number of registrations may be understood with the fact that just after three months of JEE Main 2019, candidates would face their board exams.

Moreover, those candidates who are not appearing in the January slot would be provided with an opportunity of appearing in April slot for the same exam and those who already took the exam in January may also reappear for JEE Main in April. Higher score would be considered valid at the time of admissions.

JEE Main is the most important exam for any engineering aspirant. It is also considered as a qualifying exam for JEE Advanced on the basis of which the student gets admitted to the 23 IITs. Apart from this, candidate may seek admission into IIITs, NITs and CFTIs.

JEE Main rank is used for admissions in various state level institutions in Odisha, Madhya Pradesh, Nagaland and Uttarakhand. Admit cards for JEE Main 2019 would be released on Dec 19, 2018 on official website of JEE Main i.e. jeemain.nic.in. Here are the steps to download your hallticket.

Steps to Download JEE Main Admit Card:-

  • Visit the official website.
  • Login using your credentials (ID and password).
  • Admit card will get displayed.
  • Download the admit card.

JEE Main 2019: NTA Releases Official Notification for CBT Exam

National Testing Agency (NTA) is the new organizing authority for national level entrance examinations such as UGC-NET, CMAT, GPAT, NEET and JEE Main 2019. Another major change introduced this year is introduction of CBT (Computer Based Test) in the above mentioned exams with exception to NEET. NTA released an official notification for CBT with detailed instructions to take the test in online mode on September 27, 2018.

As per the report, all the above-listed examinations will be conducted through Computer Based Test i.e. CBT wherein the candidates will have to give the exam online on a computer within the stipulated period of time. With the aim of clearing the air of doubts lingering regarding the exam, NTA has released a notification which comprises of the general guidelines and procedures to be followed for the CBT Exam.

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The first phase of JEE Main 2019 is slated from January 06 to January 20 in multiple seatings. JEE Main Application Process closes on September 30 while the admit card for JEE Main is expected to be released on or after December 17. The registration fee can be filled by October 1st, 2018 through online mode or by using bank challan.

Guidelines for JEE Main 2019 Online Examination

The official notification for CBT contains detailed instructions for candidates to take the exam successfully.

Marking of answers

The answers can be changed at any time during the examination. In order to save the answer, the candidate must click on the “Save & Next” button. It is immensely important for the candidate to ensure s/he clicks the “Save & Next” button after responding to any answer or else the answer won’t be counted as marked.

In case the candidate wants to mark the question for review (without answering it), they must click on “Mark for Review & Next” button.

Changing of answer

As mentioned, the candidate can change their answer anytime during the examination. They have the option of changing the previously saved answer of any questions during the entire test. In order to change the answer that has been already answered, the candidate must follow the procedure:

  • Click on the corresponding question from the Question Palette.
  • Then click on “Clear Response”. This option lets you clear the previously answered response.
  • Later on, the candidate can follow the procedure to answer the questions like that of others.

Allocation of Computers

Each candidate will be allotted a separate computer. Herein, they would be required to feed in their login details on the computer about the day of the exam.

Starting of Test

Once the login details are fed in the computer, the candidate will be able to see the entire instruction of the examination listed on the screen. Candidates are advised to go through the entire instructions carefully regarding the type of questions and marking scheme before proceeding to take up the test.

Countdown Timer

A countdown timer would be displayed on the top right side of the screen. As soon as the timer reaches zero, the examination will end. Candidates will not be required to submit or end the examination. It will end automatically as soon as the countdown timer reaches zero. However, candidates must ensure to save their responses (whether changed ones or unanswered) after answering every question within the time frame or else the answer would be rejected.

In addition, candidates will be provided with blank sheets for doing rough work or calculations. In order to acquaint the students with the CBT format and the examination, candidates can download the mock tests available on the official website of NTA www.nta.ac.in for familiarising with the scheme of examination and gaining hands-on practice.

JEE Main 2019 Slot Booking by NTA

NTA has scraped the slot booking process. As per the new system, JEE Main slot booking process will be conducted by NTA and candidates will not have the leisure to select their slot. The NTA (National Testing Agency) that happens to be the exam conducting body will be allotting the date, shift, and timing. They will be randomly allocating the slots for registered candidates. The allotment will be conducted by NTA using computer software on a random basis. The allotment will begin after the closure of application date.

The slot booking for JEE Main comprising of date and shift booking is an important aspect of all students who are appearing for JEE Main 2019. However, as per reports, the JEE Mains has brought about few changes. The examination will now be conducted in two shifts and 8 settings. Furthermore, the Mains will be conducted in two sessions (i.e. in January and April).

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The date and time shift for both Paper I and Paper II will be notified by October 05 while the examination centre/city for JEE Main 2019 will be notified by October 21 on the official site. Many students expected to have the advantage of slot booking but NTA due to logistics and other reasons seems to have revoked the facility.

About JEE

JEE or Joint Engineering Entrance Mains is one of the most difficult entrance examination conducted for students who aspire to pursue Engineering (B.E./ B.Tech) or Architecture (B.Plan/ B.Arch) in the future. It is one of the important examinations which deems eligibility of candidates seeking admission in top IITs across the country. The examination comprises of two papers. The paper I that deals with Engineering and Paper II is for Architecture.

Notification by NTA

JEE Main examination has brought about important changes in aspects of conduction of examinations and the slot allotments. The examination will now be conducted in 8 settings and candidates will be required to book their shift. According to reports published, the Paper I for Engineering will be conducted in two shift timings one in the morning and other in the evening whereas the Paper II for Architecture will be conducted in the first shift i.e. Morning shift only.

Some of the other details mentioned in the notification are as follows:

  • Paper 1 will be for engineering students, aspiring to pursue B.E./B.Tech.
  • It will comprise of questions from Mathematics, Physics, and Chemistry.
  • The Paper 1 will be conducted on online mode only.
  • The schedule will be conducted in two shifts which will be from 9.30 – 12.30 and 2.30 – 5.30.
  • Paper 2 will be for Architecture students who aspire to take up B.Plan/ B.Arch.
  • It will comprise of questions from Mathematics, Aptitude Test and Drawings.
  • The Mathematics exam and Aptitude Test for Paper II will be conducted through online mode, whereas the Drawing Test will be conducted Offline (pen and paper mode).
  • Paper 2 will be conducted only during the 1st shift i.e. 9.30 – 12.30

Notification of dates

The application form for JEE Main 2019 is available from September 1, 2018. The for registration closes on September 30, 2018. Candidates are advised to apply early as soon as the process commences on the official website of National Testing Agency (NTA).

The NTA will allocate slots to candidates which will be based on “First come, First serve” basis. The candidate can choose a slot for the exam at the time of filling the application, however, the final decision of the slot will be done by NTA that will be selected randomly through a computerized process.

The final date and time slot along with allotted centre of examination will be printed on JEE Main Admit Card.

Steps to Download JEE Main Admit Card 2019

JEE Main 2019 Admit Card for Phase I is tentatively scheduled for release on December 17, 2018. Candidates can download from the official site of NTA. Note that the admit card will be issued for successful applicants. Here are the steps to download admit card successfully:

  1. Go to the official website of National Testing Agency on www.nta.ac.in Or Go to the official website of JEE at www.jeemain.nic.in
  2. Click on “Admit Card for JEE Main 2019” link
  3. Enter JEE Main 2019 Application Number and Password along with security pin.
  4. Click on the submit button
  5. Admit Card is displayed in your browser.
  6. Check for all the details printed on the card and in case of any discrepancy, report to the authorities immediately.
  7. Finally, download the card in your system and take multiple printouts of the same for future purposes.

JEE Main Paper 2 Eligibility Criteria Revised, NTA Releases Official Notice

The eligibility criteria for taking admissions to B.Arch and B.Planning has been updated by COA (Council of Architecture). NTA ( National Test Agency) has released an official notice with respect to candidates applying for JEE Main Paper 2.

As per the change, to take admissions in B.Arch or B.Planning, candidate must have Physics, Chemistry and Maths as main subjects. Along with this, candidate must score a minimum of 50% in each of the mentioned subjects. The aggregate percentage of the candidate is mandatory to be 50% in 10+2.

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The revised JEE Main Eligibility Criteria for B.Arch course is stated as under : “No candidate shall be admitted to architecture course unless she/he has passed an examination at the end of the 10+2 scheme of examination with 50% marks in Physics, Chemistry and Mathematics and also 50% marks in aggregate of the 10+2 examination”.

JEE Main Paper 2 Eligibility Criteria
The Council of Architecture has decided to bring this change in its Council of Architecture Regulations, 1983. Earlier, to be eligible for taking admissions to B.Arch and B.Planning, the aggregate percentage of the 10+2 standard required was 50% and the candidates must have studied maths as a subject in 10+2.

However after the amendment, candidate must have scored 50% each in Maths, Physics and Chemistry separately and should have an aggregate of 50% in class 12th.

According to a statement from NTA, the amendment was already published in June 6, 2017 but comes into effect from academic session 2019-2020.

Major Changes in JEE Main 2019

  • From this year, JEE Main would be conducted by NTA.
  • NTA would be taking the exam twice in a year, once in Jan and the other in April 2019.
  • Candidates may take one exam from both the slots or may take exam in Dec as well as April.
  • Higher obtained marks out of the two attempts would be considered for preparing admission list/AIR.
  • Exam will be held in multiple slots across different dates.
  • However, no slot booking facility is available. NTA to announce the allotted cities and date & time slot.
  • Exam would be held in online mode only. NTA has scrapped the pen and paper based mode.
  • Students may also take free practice tests in the exam format to be aware of it at practice centres.

Online registration process for first phase of JEE Main 2019 started from Sep 1, 2018 and closes on Sep 30, 2018. Candidates can fill up the application form on official website of NTA that is nta.ac.in.

Due date for paying online fees is Oct 1, 2018 by 11:50 pm. And if a student wants to update the filled details of application form, he/she may do the same from Oct 8, 2018 till Oct 14, 2018.

NTA will announce the exact time and date slot by October 05 while the city of examination for JEE Main Paper 1 and Paper 2 will be intimated by October 21.

The admit card of JEE Main (January Phase) is tentatively scheduled for release on December 17 on official website of NTA and the exam is likely to be held in January 2019.

Online Lectures by IIT Professors for JEE Main 2019 Uploaded on nta.ac.in

NTA (National Test Agency) has launched online content lecture series for aspirants of JEE Main 2019 and NEET 2019 delivered by faculty from IITs. This videos are part of the IIT PAL (Professor Assisted Learning) initiative which is another in line of major efforts taken by NTA and MHRD to facilitate students’ preparations using free and self-sustained coaching methods for JEE Main Preparation.

Several lectures are provided by IIT professors on various topics in accordance with the syllabus of exam. Lectures are dispensed on Maths, Physics, Chemistry and Biology.

With this initiative, students would have an easy reach to different topics from the portion of JEE Main and NEET 2019 syllabus. The lectures can be obtained from the official website of NTA i.e. nta.ac.in.

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Subject wise segregation is done in video series making it more organized for the students. They may browse the video by clicking on the link and then selecting subject and the topic they are looking for. Links for these online content lectures are mentioned on official website.

Youtube and official website contains a range of online lectures by IIT professors and other subject matter specialists (about 50-60). Average duration of these lectures is about 50 minutes. Candidates may browse them on their smartphones in accordance to their need and preference with the help of ‘Swayam’ platform which is part of the MHRD initiative.

Subject Wise Uploaded Videos

The IIT PAL Videos uploaded for JEE Main 2019 and other exams pertain to various topics covered under each subject. The list of all the topics are provided below for better clarity.

Mathematics – Quadratic equations, Limits, Straight lines, Complex Numbers, Three Dimensional Geometry, Permutation and Combination, Circles, Matrices, Statistics, Binomial Theorem etc.

Chemistry – Organic Compounds, Redox Reactions, Solutions, Organic Chemistry, Coordination Compounds, States of Matter: Gases and Liquids, Electrochemistry, Chemical Thermodynamics, Polymers etc.

Biology – Photosynthesis and Respiration, Cell Structure and Function, Genetics and Evolution, Human Physiology, Ecology, Plant Physiology etc.

The online registration for JEE Main 2019 – January Phase closes on September 30 while the exam is scheduled for January 06 to January 20. Phase 2 of JEE Main 2019 will be carried out from April 06 to April 20. JEE Main Registration for April session from February 08. Students applying for both the phases can use these handy tutorials to take their JEE preparation to the next level.

2.7 Lakhs Computers Distributed by Government for JEE Main Test Practice Centers

In a bid to restore the confidence of candidates appearing for JEE Main and other national level examinations, Government has distributed 2.7 lakhs computers to the students for JEE Main Test Practice Centers. The move has come in wake of doubts creeping among aspirants concerning CBT mode and MHRD & NTA’s joint effort in allaying any fears among candidates by providing ample platforms for candidates to prepare for the upcoming examination.

It is done in order to facilitate the students who do not have computers or smartphones of their own. National Testing Agency(NTA) has launched 3,404 test practice centres (TPCs) in 662 districts on Sep 16, 2018.

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The practice centres enables a candidate to register and take practice computer based test (CBT) for JEE Main and UGC-NET free of cost. Candidates can register for the test practice centers on the official site of NTA , i.e., nta.ac.in using their Google or Facebook Account.

Besides, NTA has also provided the link for online mock test on their own website to facilitate students with access to computer and internet connections to prepare for the examination at their preferred location. Another prominent effort in this direction is to upload the lectures from various IIT Professors for JEE Main 2019 on the official website.

JEE Main Test Practice Centers

Launch of Mobile App by NTA for JEE main and UGC-NET 2018

The launch of mobile app by NTA for JEE main and UGC-NET 2018 will help the students to avail the free online computer based tests from their mobile phones or computers. Uttar Pradesh, Maharashtra and Kerala have 300 practice centres each. A trial of free mock tests was held on Sep 8 and Sep 9, 2018.

A total of 2,452 students took the free practice test at 96 TPCs all over the country. Results and analysis were immediately notified to the candidates after the exam. Candidates were also given feedback on their performance in the practice test so that they may start working on their weak points.

“No student would be at the disadvantage of not appearing for the exam due to lack of resources”, said HRD minister Prakash Javadekar. Also he interacted to 1,993 candidates through Google Hangout asking for their suggestions to make the exam system more easy and accessible for all.

Online Registration for JEE Main Test Practice Centers

NTA Student App is available on play store by which students can register for JEE main and UGC-NET 2018 exam. Registration can be also done through NTA website. The service has been activated so that the students can avail the practice tests anywhere regardless of their location.

Steps to Register for JEE Main Test Practice Centers

  • Visit NTA’s official website, nta.ac.in
  • On the home page, click on the link “Student Registration for Test Practice Center”.
  • Next up, you’ll have the option to login using Google or Facebook Account. Choose any one.
  • After registration, candidates will now have to complete remaining four steps to complete the process.
    1. First, fill up personal details like first name, last name, date of birth, age, father’s name, upload recent photograph and id proof
    2. Next, add contact details such as email id, mobile number, residential address, state, district, city, and pin code for official correspondence.
    3. Also add information about academic details such as last attended school or institute’s name and your enrollment number (optional).
    4. Finally, add details of previous number of attempts for JEE Main examination and hit ‘submit’.

The remaining steps will be related to select Centre and Booking Appointment:

  • Candidates will have to pick 5 centers from the list of test practice centers (TPCs) and provide them rating between 1 to 5 in order of their preference.
  • Pick the date you are planning to appear for JEE Main Mock Test at the test practice center.
  • Submit your preferences.
  • Verify the selected centers and click on “Confirm Appointment” to complete the process.
  • An acknowledgement screen will confirm the choice of practice center preference and confirmation of TPC registration.

On successful registration for JEE Main Test Practice Centers, candidates will also receive an approval text message on their registered mobile numbers.

Aadhaar not Mandatory for JEE Main Registration, NTA Releases Official Notice

JEE Main 2019 is going to be held from January 6 to January 20 this year. The registration for JEE Main started on September 01 and would wind up on Sep 30, 2018. Candidates can register online only at official website of NTA, nta.ac.in. However, since the beginning of process several queries were made concerning the requirement of aadhaar details in application form of JEE Main 2019 and UGC-NET Dec 2018.

In a response to these queries, NTA (National Test Agency on Tuesday, 11 Sep, 2018 published a notice clarifying that filling up of Aadhaar card number in the application forms is not necessary. The official notice by NTA clearly indicates, “it is hereby clarified that while filling in online Application Form and as per the ‘Replica of Application Form’ given in Annexure VIII (page 39-40) (UGC-NET Bulletin December 2018) in the drop down box regarding ‘Identification Type’ and as also given on page 11, the Aadhaar number is only one of the types of identification and is not mandatory”.

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JEE Main 2019 Aadhaar Notice

This now is expected to clear the confusion for all JEE aspirants. NTA has also mentioned that in place of Aadhaar Number, any government identity number would be accepted. It may be ration card number, bank account number, passport number etc. In the application form of JEE Main and UGC-NET which are being filled, candidates would be provided to enter any valid government identity number.

 

How to Apply for JEE Main 2019?

JEE Main Registration can be completed through the website – nta.ac.in or jeemain.nic.in. Filling up the complete form consists of four stages. Let’s browse through the steps one at a time:

  1. Registration- This is the very first page to be filled while applying online for JEE Main 2019. Here you would be submitting your basic details such as
  • state of eligibility
  • state from where the candidate has passed class 12th
  • identification ID type and identification ID
  • candidate’s name
  • date of birth
  • gender
  • security pin.
  1. Application Form- After successful registration, you would be asked to submit other details which includes:
  • personal details
  • details related to examination
  • academic details
  • contact details
  • guardian details
  • in the end you would be setting password which would be further used to login by the candidate to check the status.
  1. Uploading of documents (scanned) – After filling-in the required details in the application form, candidates are required to upload the asked documents.
  • What should be kept in mind is, the documents should be in prescribed form otherwise they won’t get uploaded.
  • After clicking on “upload scanned images”, you would be asked to upload photo and signature of the candidate.
  • The specifications for to-be-uploaded documents would be mentioned there already.
  1. Application fees payment- The last step is to pay the application fees. After verifying the details that you have submitted earlier, make payment for prescribed application fees. Payment can be done through credit/debit card, net banking and offline through e-challan. Oct 1, 2018 is the last date to deposit payment in online mode.

The application fee for JEE Main 2019 is tabulated below:

Paper/Category Paper 1 or 2 Paper 1 and 2 Both Paper 1 or 2 Paper 1 and 2 both
Those who’s Exam Centre is in India Those who’s Exam Centre is out of India
Offline Modes (Pen & Paper Based) General/OBCs (Boys) 1000 1800 2500 3800
SC/ST/PwD/All Girls 500 900 1250 1900
Online Modes (Computer Based) General/OBCs (Boys) 500 1300 2500 3800
SC/ST/PwD/All Girls 250 650 1250 1900

 

Top 20 Percentile Cutoff Marks for Class XII Exam

JEE Main 2019 is underway with commencement of registration for the January session. Most of the students are worried about filling all the details carefully in JEE Main Application Form and ensuring that feel the desired eligibility criteria to avoid rejection. A lot of candidates search for top percentile cutoff marks in JEE Main.

JoSAA is responsible for releasing the top 20 percentile for JEE Main and JEE Advanced. The top 20 percentile cut off marks is released separately for IITs and other institutes (NITs, IIITs and CFTIs) on the official site, jossa.nic.in. Although the top 20 percentile is released after the result declaration, candidates must be aware about the previous year trends.

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Get latest news and updates of JEE Main 2019 through email or SMS by entering your details in below given form:

What is the top 20 percentile?

Each year as many as a million of students appear for JEE and NIT entrance examinations with the view of gaining admission in top engineering institutes. Even though the marks secured in Class 12th is no longer considered for JEE Main Rank Calculation, yet it is a determining factor for admission to IITs, NITs, IIITs and CFTIs. However, not all the state education boards release marks in the form of percentage. Therefore, the organizing authority will also consider candidates failling in the top 20 percentile while determining their eligibility.

Top 20 Percentile for JEE main

Eligibility Criteria

In order to secure a place in JEE or NITs, candidates will have to fulfill the following requirements:

  • The minimum eligibility is to secure 75% for General Category. For reserved category belonging to SC/ ST/ PwD, the minimum eligibility is scoring 65% in the class 12 examination.

or

  • They must fall in the top 20 percentile category in class 12 of their respective boards or qualifying examination.
  • Even though a candidate fails to secure 75% in their class 12th, they still hold opportunity for appearing in the entrance examinations on the basis of top 20 percentile marks.
Get latest news and updates of JEE Main 2019 through email or SMS by entering your details in below given form:

How are class 12th marks calculated for admission to IITs and NITs

The calculation of score will be as follows:

  • The score of candidates will be calculated for any 5 subjects which in total will be calculated out of 500. These five subjects will include Physics, Chemistry, and Mathematics as compulsory subjects out of the five. The other two include one language subject and one other subject (expect from the four already selected). In this manner, the total secured in the five subjects with aggregate marks 500 will be taken into account.
  • In case, a candidate has taken two language subjects, then the subject with a higher score will be considered.
  • If the marks of any subject are not awarded out of 100, then in such cases, the score will be scaled to make it out of 100. For example – if a candidate secures 50 out of 80, then the calculation of score will be as follows: (65/80)*100 = 81%
  • If a candidate has appeared for Class 12th examination in the year 2016 and again reappears in 2017 for improvement in any one or two subjects, then the marks secured in 2016 will be considered and not that of 2017.
  • However, in case a candidate had appeared in 2016, yet reappears for improvement in all 5 exams conducted in 2017, in that case, the scores of the year in which the candidate has score more marks will be considered.

Difference Between Percentage and Percentile

Often candidates get obscured of the difference between a percentage score and percentile. However, both the terms are completely different from one another. A percentage score is marks obtained by a candidate from the aggregate of 100. On the other hand, a percentile is a term used to define the percentage a candidate secures below particular marks.

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Example – Suppose a candidate has secured 85 percent marks. This is the marks secured out of 100, wherein he/she has scored 85. If the total is 200 it will be 170 and so on. However, if a candidate mentions he/she has scored 85 percentile, that would mean 85 percent of all other candidates who have appeared for the examination have score fewer marks than the candidate with 85 percentile.

Following are the state education boards for which JoSAA will publish top 20 percentile for JEE Main on its official website.

Andhra Pradesh Board of Intermediate Education
Assam Higher Secondary School Council
Bihar Intermediate Education Council
Central Board of Secondary Education
Banasthali Vidyapith
Aligarh Muslim University Board of Secondary & Sr. Secondary Education
Chhattisgarh Board of Secondary Education
Council of the Indian School Certificate Examinations
Goa Board of Secondary and Higher Secondary Education
Gujarat Secondary Education Board
Haryana Board of Education, Bhiwani
Himachal Pradesh Board of School Education
Jammu and Kashmir State Board of School Education
Jharkhand Academic Council
Karnataka Board of Pre-University Education
Kerala Board of Public Examinations
Madhya Pradesh Board of Secondary Education
Council of Higher Secondary Education, Manipur
Meghalaya Board of School Education
Mizoram Board of School Education
Nagaland Board of School Education
National Institute of Open Schooling
Punjab School Education Board
Telangana State Board of Intermediate Education, Hyderabad
Telangana Open School Society Hyderabad
Tripura School of Secondary Education
Maharashtra State Board of Secondary and Higher Education
U.P. Board of High School & Intermediate Education
Board of Secondary Education Rajasthan
Council of Higher Secondary Education, Odisha

 

JEE Main Previous Year Question Papers

NTA (National Testing Agency) has finally come into existence and the rollout of the official notification for JEE Main 2019 January session has set the engineering exam season underway. JEE Main is scheduled from January 06, 2019 to January 20, 2019 in online mode and the application process has already commenced.

This simply means all those who are preparing to crack JEE Main 2019 have tentatively four months in their hand. At this juncture of your preparation what is crucial is to test your speed and accuracy and find the weaker links during the preparation.

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For assessment of preparation, there is nothing better than to solve full-length mocks and sample papers. Along with all this one crucial but ignored thing is practicing of previous years question papers. Students being loaded with material, test series and reference books often forget to have a look at the previous year papers.

Solving a full-length previous year question paper not only gives idea about the difficulty level of questions but also fills you with confidence. The confidence which you would gain by solving questions of previous years papers would aid you to score better in your practice mocks and eventually in the JEE Main 2019 exam.

Highlights of JEE Main Exam Pattern

JEE Main 2019 exam would be conducted in online mode only. The pen and paper based exam is scrapped from this year onwards. However, there are no major surprises expected in the JEE Main 2019 exam. Candidates who are preparing for JEE Main 2019 need to familiarize themselves with the pattern of the exam.

For your reference the pattern of the exam is tabled below:

Mode of Exam Online
Sections in paper 3 (Physics, Chemistry, Mathematics)
Nature of questions asked 90 questions (30 Questions each from Physics, Chemistry, Mathematics)
The time duration of the exam 180 Minutes (3 Hours)
Maximum Marks 360
Marking pattern 4 Marks for the correct answer. ¼th marks to be deducted for the wrong answer
Subjects covered Physics, Chemistry, and Mathematics

Practice JEE Main Mock Test

In an attempt to make the transition to online mode smoother for aspirants and familiarize the candidates with the pattern, NTA has uploaded a full-length practice mock for JEE Main 2019 on its official website https://www.nta.ac.in/.

Candidates can now access the mock on the official NTA website. Besides, on MHRD’s instructions NTA has also set up 3000 new centers where candidates can avail the mock test by registering themselves on the official site of JEE Main 2019.

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Download JEE Main Mock Test

To ease your task and let you focus more on your study and question practice we are here providing you the previous year JEE Main question papers. The question papers are arranged in a year-wise manner in the below-mentioned table for candidate’s reference.

Year Question Paper
2018 Click Here To download JEE Main 2018 Question Paper
2017 Click Here to download JEE Main 2017 Question Paper
2016 Click Here to download JEE Main 2016 Question Paper
2015 Click Here to download JEE Main 2016 Question Paper
2014 Click Here to download JEE Main 2014 Question Paper
2013 Click Here to download JEE Main 2013 Question Paper with solutions

The past five years papers of JEE Main that are listed above would help you to get a comprehensive idea of the types of questions asked from each topic and what would be the level of difficulty of the questions.

JEE Main 2019 Normalization Procedure, Tie Breaking Norms

JEE Main 2019 will be conducted by National Testing Agency and the results shall be announced on January 31, 2019. The coming year will see some major changes in the format of JEE Main 2019 precisely due to introduction of two attempts for the same year and reintroduction of normalization process.

The merit list for JEE Main 2019 for both the papers will be prepared jointly. The candidates appearing for the second attempt will have a separate merit list. But to determine the final AIR, NTA would take the best of both the attempts.

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The information bulletin issued on the official website of JEE Main states the purpose and procedure of normalization procedure. Prior to this the former JEE Main conducting body, Central Board of Secondary Education (CBSE), had introduced normalization procedure to equate class 12th examination in order to bring different state boards at par with each.

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The procedure was called off as board examination marks couldn’t be put to proper use to realize All India Rankings. In the year 2019, NTA will do normalization but for a very different purpose i.e. to normalize the difficulty level of exams to be conducted in different shifts.

The Purpose

The information bulletin on Normalization procedure states, “In spite of all efforts of maintaining equivalence among various question papers, the difficulty level of these question papers administered in different sessions may not be exactly the same. Some of the candidates may end up attempting a relatively tougher set of questions when compared to other sets”.

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Consequently, candidates attempting tougher paper are likely to get lower marks in comparison to those attempting easier paper. The remedy to which is normalization procedure based on percentile score. This will ensure that the candidates appearing in the examination should neither benefit nor loose due to the difficulty level of the entrance.

What is Normalization Procedure

Normalization procedure as we all know is nothing new and many national level testing agencies have been following the practice to overcome disparity occurring in multiple testing formats. It compares candidates’ scores through established methods across multiple sessions to formulate a final merit list. NTA will be using percentile equivalence method for the same.

Before we delve further on step by step procedure, for students and other readers it would be difficult to understand normalization procedure until they don’t understand basic terminologies like –

Percentile Scores: The scores based on the relative performance of number of candidates appearing for the exam are the Percentile Scores. The marks (raw scores) obtained by the candidates are brought down to a scale ranging from 100 to 0 for each session of test takers. In other words a Percentile Score is the percentage of candidates scoring equal to or below (raw scores) the particular percentile for that examination.

Raw Score: Original marks of a candidate which he or she has obtained based on the marking scheme. In JEE Main for each correct answer there are 4 marks and for each incorrect answer there will be negative marking by 1 mark.

Subject Percentile Score: This is again percentile score but for the given subjects. In JEE Main this would calculated separately for each subject – Mathematics, Chemistry and Physics.

Merit List: The merit list will determine the All Indian Ranking of candidates on the basis of best of both the attempts and normalization procedure.

NTA will use predefined formula for determining overall and subject wise percentile scores.

Step by Step JEE Main Normalization Procedure Exaplanation

Step-1: Distribution of Examinees
The distribution of examinees for different shifts in a day would be done to have approximately equal number of candidates for each shift. In case there are more numbers of days or number of shifts then examinees would be divided accordingly.

This is to overcome any bias that may arise due to distribution of candidates appearing in the examination. Further, with over Lacs of candidates taking examination from different parts of the country the possibility of such biasness would be zeroed down.

Step-2: Preparation of Results
The results for each session shall be prepared in the form of Raw Scores and Percentiles Scores. NTA will also prepare scores separately for each subject and the Total.

JEE Main Normalization Formula

Step-3: Score Compilation and Preparation of AIR
The percentile scores as obtained from Step 2 shall be finally considered as NTA scores based on which results would be compiled to announce AIR. Based on theses ranking candidates will qualify for JEE Advanced and admissions to IITs, IIITs and GFTIs.

Tie Breaking Process in JEE Main 2019

The JEE Main 2019 also states clearly the procedure to break down ties between candidates. It will be done by taking the following parameters into consideration (listed in the order of preference):

·       The Percentile Scores will be calculated up to 7 decimal places.

·       Higher percentile in Mathematics

·       Higher percentile in Physics

·       Higher percentile in Chemistry

·       Lastly, to the candidate who is elder in age.

It looks all positive right now and students can feel relieved because of the format changes about to take place in JEE Main 2019. Moreover, two attempts is a welcome change in format which shall reduce the dropout numbers.